Below is a toy function with one way of doing it. There are bound to
be better ways :)
function(niter = 10, time.out = 3) {
pretend.task <- function() {
Sys.sleep(0.5)
}
start <- proc.time()
for (iter in 1:niter) {
pretend.task()
cur <- proc.time() - start
if (cur[3] > time.out) return("timed out")
}
return("completed")
}
On 7 December 2010 13:04, Santosh Srinivas <santosh.srini...@gmail.com> wrote:
> Hello Group,
>
> I have an R-function that works fine for most part but sometime runs into a
> long loop! (I'm lazy and short on time to debug right now so want to do
> something easy)
> For my purpose, it is ok to make few errors .... is there a way I can put a
> timeout on a function and the r-process needes to move on to the next step?
>
> Thank you.
> S
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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