As Nick suggested, you're confusing the name of an object with the name(s) of its elements.
Study this example: > > lamda <- 0.2 > lamda [1] 0.2 > lamda <- c(g=0.2) > lamda g 0.2 > lamda <- c(1,3,4) > lamda [1] 1 3 4 > lamda <- c(g=1, x=3, foo=4) > lamda g x foo 1 3 4 lamda is now a numeric object of length 3, that is, it has 3 elements. Each of the elements has a name. > names(lamda) [1] "g" "x" "foo" The name of the object itself is "lamda". The names of its elements are "g", "x", and "foo". To get the value of the element named "x" do this: > lamda['x'] x 3 lamda['x'] return the value of the element named "x", no matter what position it is. Compare: > lamda[2] x 3 Which returns the value of the second element, no matter what it is named. An object named "g", and the element of lamda named "g" are completely independent of each other: > g <- 0.5 > > g [1] 0.5 > lamda['g'] g 1 Hope this helps -Don -- Don MacQueen Environmental Protection Department Lawrence Livermore National Laboratory 925 423-1062 On 11/26/10 12:12 AM, "Mike Gibson" <megalop...@hotmail.com> wrote: > >I must be missing something. > >I first state my g parameter with: > >> lamda<-c(g=0.2) > >However, when I do the next step R is telling me "object g not found" >Here is my next step: > >> Q<-exp(g) > > >??? > >Any help would be greatly appreciated. > >Mike > [[alternative HTML version deleted]] > >______________________________________________ >R-help@r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
