Hello Mike. I'm not clear on why you would want to "state your g parameter" (In fact, I don't even know for sure what you mean by that) with > lamda<-c(g=0.2)
If you want a variable (vector) g containing 0.2, why don't you simply do: > g<-0.2 If you need that lamda thing for some reason later on, you can always do: > lamda<-c(g=g) Afterwards to get the same effect. If you have some reason not to do this: With your statement, you create a vector lamda, with one item in it, and that first and only item is named "g". So from your statement, you can access g by: lamda["g"] as in: > Q<-exp(lamda["g"]) It looks like you've got a misunderstanding of how R variables work, but maybe I just misunderstood your question... HTH, Nick Sabbe -- ping: nick.sa...@ugent.be link: http://biomath.ugent.be wink: A1.056, Coupure Links 653, 9000 Gent ring: 09/264.59.36 -- Do Not Disapprove -----Original Message----- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Mike Gibson Sent: vrijdag 26 november 2010 9:13 To: r-help@r-project.org Subject: [R] small problem in coding I must be missing something. I first state my g parameter with: > lamda<-c(g=0.2) However, when I do the next step R is telling me "object g not found" Here is my next step: > Q<-exp(g) ??? Any help would be greatly appreciated. Mike [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
