Its a bit tricky if you want to get it to work exactly the same as
Excel even in the presence of runs but in terms of the R approx function
I think percentrank corresponds to ties = "min" if the value is among those
in the table and ties = "ordered" otherwise so:
percentrank <- function(table, x = table) {
table <- sort(table)
ties <- ifelse(match(x, table, nomatch = 0), "min", "ordered")
len <- length(table)
f <- function(x, ties)
(approx(table, seq(0, len = len), x, ties = ties)$y) / (len - 1)
mapply(f, x, ties)
}
# test
tab <- c(1, 1, 2, 2, 3, 3)
percentrank(tab, 2:6/2) # c(0, .3, .4, .7, .8)
which is the same result as Excel 2007 gives.
On Dec 1, 2007 6:37 AM, tom soyer <[EMAIL PROTECTED]> wrote:
> Hi,
>
> Does anyone know if R has a built-in function that is equvalent to Excel's
> percentrank, i.e., returns the rank of a value in a data set as a percentage
> of the data set?
>
> Thanks,
>
> --
> Tom
>
> [[alternative HTML version deleted]]
>
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