I don't see one but that means nothing. I think you can write such a function in a few minutes
Will something like this work or am I missunderstanding what Excel's percentrank does ? aa <- rnorm(25); aa # data vector percentrank <- function(x) { var <- sort(x) p.rank <- 1:length(var)/length(var)*100 dd <- cbind(var,p.rank) } pr <- percentrank(aa); pr --- tom soyer <[EMAIL PROTECTED]> wrote: > Hi, > > Does anyone know if R has a built-in function that > is equvalent to Excel's > percentrank, i.e., returns the rank of a value in a > data set as a percentage > of the data set? > > Thanks, > > -- > Tom > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.