Sorry misread the question.
Function arev() takes a second argument that specifies
which dimensions to flip:
> b <- matrix(1:9,3,3,byrow=T)
> b
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
> arev(b,1)
[,1] [,2] [,3]
[1,] 7 8 9
[2,] 4 5 6
[3,] 1 2 3
>
On 23 Oct 2007, at 11:45, Rainer M Krug wrote:
> Hi
>
> I have a vector
>
> x <- c(1, 2, 3, 4, 5)
>
> and I want to "flip" it around, i.e. I need
>
> 5, 4, 3, 2, 1
>
> Is there a ssolution apart from
>
> y <- x[length(x):1]
>
>
> I am also looking for the same for a matrix M, i.e.
>
> 1 2 3
> 4 5 6
> 7 8 9
>
> should become
>
> 7 8 9
> 4 5 6
> 1 2 3
>
> again, I am using
>
> M[1:dim(M)[1], dim(M)[2]:1]
>
>
> Thanks
>
> Rainer
>
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--
Robin Hankin
Uncertainty Analyst
National Oceanography Centre, Southampton
European Way, Southampton SO14 3ZH, UK
tel 023-8059-7743
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