Thanks Katharine that answers my vector question. The suggestion for the matrix is interesting and I would have never thought about theat.
Thanks Rainer Katharine Mullen wrote: > One way: > >> x<-1:9 >> rev(x) > [1] 9 8 7 6 5 4 3 2 1 > > for x as the matrix you gave: >> x > [,1] [,2] [,3] > [1,] 1 2 3 > [2,] 4 5 6 > [3,] 7 8 9 >> >> apply(t(x),1,rev) > [,1] [,2] [,3] > [1,] 7 8 9 > [2,] 4 5 6 > [3,] 1 2 3 > > > On Tue, 23 Oct 2007, Rainer M Krug wrote: > >> Hi >> >> I have a vector >> >> x <- c(1, 2, 3, 4, 5) >> >> and I want to "flip" it around, i.e. I need >> >> 5, 4, 3, 2, 1 >> >> Is there a ssolution apart from >> >> y <- x[length(x):1] >> >> >> I am also looking for the same for a matrix M, i.e. >> >> 1 2 3 >> 4 5 6 >> 7 8 9 >> >> should become >> >> 7 8 9 >> 4 5 6 >> 1 2 3 >> >> again, I am using >> >> M[1:dim(M)[1], dim(M)[2]:1] >> >> >> Thanks >> >> Rainer >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
