On 4/10/2007, at 7:50 AM, Peter Dalgaard wrote:
> Rolf Turner wrote:
>>> Does it even work? (What if it is the first or the 2nd level that
>>> is absent?
>>
>> Yes it works. What's the problem?
>>
>> To beat it to death: if the second level of fff is absent
>> then fff will consist entirely of 1's and 3's,
>> and so c("U","A","S")[fff] will consist entirely of U's and
>> S's. I can then set the levels to be
>> c("U","A","S") and get what I want.
> You didn't say that fff was numeric.
All factors are numeric.
> If fff is a factor, then we have the problem:
>
> > attach(read.table(stdin(),header=T))
> 0: fff
> 1: Unit
> 2: Scholarship
> 3: Scholarship
> 4: Unit
> 5:
> > c("U","A","S")[fff]
> [1] "A" "U" "U" "A"
My original fff is a factor with levels c
("Unit","Achievement","Scholarship"). If you make that
adjustment, you get the ``right answer''.
> Actually we have another problem too, namely sort order....
No, there is no sort order problem. See above.
[Given that the original fff has its levels in the order specified
then Unit maps to U,
Achievement to A, and Scholarship to S.]
cheers,
Rolf
P.S. ***Are*** there any risks/dangers in following Christos
Hatzis' suggestion of simply doing
levels(fff) <- c("U","A","S") ???
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