Rolf Turner wrote:
>> Does it even work? (What if it is the first or the 2nd level that is
>> absent?
>
> Yes it works. What's the problem?
>
> To beat it to death: if the second level of fff is absent then
> fff will consist entirely of 1's and 3's,
> and so c("U","A","S")[fff] will consist entirely of U's and S's.
> I can then set the levels to be
> c("U","A","S") and get what I want.
You didn't say that fff was numeric.
If fff is a factor, then we have the problem:
> attach(read.table(stdin(),header=T))
0: fff
1: Unit
2: Scholarship
3: Scholarship
4: Unit
5:
> c("U","A","S")[fff]
[1] "A" "U" "U" "A"
Actually we have another problem too, namely sort order....
Anyway, sort the labels, and
> c("A","S", "U")[fff]
[1] "S" "A" "A" "S"
If you have the data as numeric codes, then of course
factor(fff, levels=1:3, labels=c("U","A","S"))
does the trick too.
--
O__ ---- Peter Dalgaard Øster Farimagsgade 5, Entr.B
c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
(*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
