>
>
> +
> +/*
> + * This instruction performs 8-bit x 8-bit -> 16-bit signed
> multiplication
> + * and shifts the result one bit left.
> + */
> +static bool trans_FMULSU(DisasContext *ctx, arg_FMULSU *a)
> +{
> + if (!avr_have_feature(ctx, AVR_FEATURE_MUL)) {
> + return true;
> + }
> +
> + TCGv R0 = cpu_r[0];
> + TCGv R1 = cpu_r[1];
> + TCGv Rd = cpu_r[a->rd];
> + TCGv Rr = cpu_r[a->rr];
> + TCGv R = tcg_temp_new_i32();
> + TCGv t0 = tcg_temp_new_i32();
> +
> + tcg_gen_ext8s_tl(t0, Rd); /* make Rd full 32 bit signed */
> + tcg_gen_mul_tl(R, t0, Rr); /* R = Rd * Rr */
> + tcg_gen_andi_tl(R, R, 0xffff); /* make it 16 bits */
> +
> + tcg_gen_shri_tl(cpu_Cf, R, 15); /* Cf = R(15) */
> + tcg_gen_setcondi_tl(TCG_COND_EQ, cpu_Zf, R, 0); /* Zf = R == 0 */
> +
> + tcg_gen_shli_tl(R, R, 1);
> +
> + tcg_gen_andi_tl(R0, R, 0xff);
> + tcg_gen_shri_tl(R1, R, 8);
> + tcg_gen_andi_tl(R1, R1, 0xff);
> +
> + tcg_temp_free_i32(t0);
> + tcg_temp_free_i32(R);
> +
> + return true;
> +}
> +
Hi, Michael.
The way I understand the spec is that a->rd and a->rd must be between 16
and 23:
https://www.microchip.com/webdoc/avrassembler/avrassembler.wb_FMULSU.html
Is my interpretation right? If yes, where is the corresponding part in the
implementation?
Yours, Aleksandar
>
