---------- Forwarded message ----------
From: she roy <she.min....@gmail.com>
Date: 2013/8/28
Subject: Re: [Qemu-devel] trigger a gpio interrupt inside qemu
To: Max Filippov <jcmvb...@gmail.com>
I tested qemu_irq_pulse(gPl061->irq); the guest did not generate an
interrupt. so I changed to
qemu_set_irq(gPl061->irq, 1);
sleep(1);
qemu_set_irq(gPl061->irq, 0);
A lot of interrupts generated. Is it possible to generate just one
interrupt?
Thanks.
2013/8/27 Max Filippov <jcmvb...@gmail.com>
> On Tue, Aug 27, 2013 at 3:55 PM, she roy <she.min....@gmail.com> wrote:
> > How to lower it? Thank you very much!
> >
>
> qemu_set_irq(gPl061->irq, 0);
>
> Or you could try
>
> void pl061_raise_irq()
> {
> qemu_irq_pulse(gPl061->irq);
> }
>
> > 2013/8/27 Max Filippov <jcmvb...@gmail.com>
> >>
> >> On Tue, Aug 27, 2013 at 3:36 PM, she roy <she.min....@gmail.com> wrote:
> >> > Is there somebody can help me to trigger a gpio interrupt inside
> qemu? I
> >> > wrote a simple function to trigger a interrupt in pl061.c as follow:
> >> > PL061State *gPl061;
> >> > void pl061_raise_irq()
> >> > {
> >> > qemu_set_irq(gPl061->irq, 1);
> >> > }
> >>
> >> [...]
> >>
> >> > But when i call pl061_raise_irq inside qemu once, the guest run into
> an
> >> > infinite loop. it prints:
> >> > ...
> >> > irq:[927012]receive the irq at -12002...
> >> > irq:[927013]receive the irq at -12002...
> >> > irq:[927014]receive the irq at -12002...
> >> > irq:[927015]receive the irq at -12002...
> >> > irq:[927016]receive the irq at -12002...
> >> > irq:[927017]receive the irq at -12002...
> >> > irq:[927018]receive the irq at -12002...
> >> > ...
> >> > can somebody tell me what's wrong?
> >>
> >> You have raised IRQ in your pl061_raise_irq(), but you haven't lowered
> it.
> >>
> >> --
> >> Thanks.
> >> -- Max
> >
> >
>
>
>
> --
> Thanks.
> -- Max
>
