Is there somebody can help me to trigger a gpio interrupt inside qemu? I
wrote a simple function to trigger a interrupt in pl061.c as follow:
PL061State *gPl061;
void pl061_raise_irq()
{
qemu_set_irq(gPl061->irq, 1);
}
gPl061 is assigned in function pl061_initfn:
static int pl061_initfn(SysBusDevice *sbd)
{
DeviceState *dev = DEVICE(sbd);
PL061State *s = PL061(dev);
memory_region_init_io(&s->iomem, OBJECT(s), &pl061_ops, s, "pl061",
0x1000);
sysbus_init_mmio(sbd, &s->iomem);
sysbus_init_irq(sbd, &s->irq);
qdev_init_gpio_in(dev, pl061_set_irq, 8);
qdev_init_gpio_out(dev, s->out, 8);
pl061_reset(s);
gPl061 = s;
return 0;
}
I installed an interrupt handler in the guest linux system:
MODULE_LICENSE("GPL");
MODULE_AUTHOR("sermonko");
int irq = 41;
char interface[] = "gpio";
int irq_handle_function(int irq, void *device_id)
{
static int count = 1;
MSG("[%d]receive the irq at %ld...\n", count, jiffies);
count++;
return IRQ_HANDLED;
}
int __init int_init_module()
{
if(request_irq(irq, irq_handle_function, IRQF_SHARED, interface, (void
*)&irq))
{
MSG("regist irq failure...\n");
return -EIO;
}
MSG("interface=%s and irq=%d...\n", interface, irq);
MSG("regist irq success...\n");
return 0;
}
void __exit int_cleanup_module()
{
free_irq(irq, &irq);
MSG("unregist irq...\n");
}
module_init(int_init_module);
module_exit(int_cleanup_module);
I start qemu using this command: qemu-system-arm -M versatilepb -kernel
output/images/zImage -drive file=output/images/rootfs.ext2,if=scsi -append
"root=/dev/sda console=ttyAMA0,115200" -serial stdio -net nic -net
bridge,br=br0
But when i call pl061_raise_irq inside qemu once, the guest run into an
infinite loop. it prints:
...
irq:[927012]receive the irq at -12002...
irq:[927013]receive the irq at -12002...
irq:[927014]receive the irq at -12002...
irq:[927015]receive the irq at -12002...
irq:[927016]receive the irq at -12002...
irq:[927017]receive the irq at -12002...
irq:[927018]receive the irq at -12002...
...
can somebody tell me what's wrong?
