hi... i have the following section of test code where i'm trying to get the attribute of a frame <frame src="....">
i'm trying to print/get the src value. the xpath query that i have displays the "src" attribute in the Xpather/Firefox plugin. however, i can't quite figure out how to get the underlying value in my test app... sxpath = "/html/frameset/frame[2]/attribute::src" # s contains HTML not XML text d = libxml2dom.parseString(s, html=1) #get the tr list tr1 = d.xpath(sxpath) url = tr1[0] #get the url/link >>semester page #link = br.find_link(nr=1) #url = link.url print "link = ",url sys.exit() err output link = <libxml2dom.Attribute object at 0xb7b7680c> -------------------------------------- i'm not sure what i need to add to the line url = tr1 to resolve the issue/error... looking over google hasn't given any real pointers... thanks -bruce -- http://mail.python.org/mailman/listinfo/python-list