Sheldon wrote: > Hi, > > I have two arrays that are identical and contain 1s and zeros. Only the
Obviously they aren't identical. They may be of same size. > ones are valid and I need to know where both arrays have ones in the > same position. I thought logical_and would work but this example proves > otherwise: >>>> a = [0,1,2,5,6,6] >>>> b = [5,4,1,6,4,6] >>>> Numeric.logical_and(a==6,b==6) > 0 >>>> Numeric.where(a==b,1,0) > 0 >>>> Numeric.where(a==6 and b==6,1,0) > 0 > > The where() statement is also worhtless here. Does anyone have any > suggestion on how to do this? print [i for i, _ in enumerate((None for v in zip(a, b) where v == (1,1)))] should give you the list of indices. Diez -- http://mail.python.org/mailman/listinfo/python-list
