Girish Sahani wrote: >>I guess it's already the case with lst = [ e for e in lst if e in pairs ] >> >> >>In [1]: lst = (1,2,3,4) >> >>In [2]: pairs=(5,) >> >>In [3]: lst=[e for e in lst if e in pairs] >> >>In [4]: lst >>Out[4]: [] > > Yes its working. I realized that i was giving an input which didnt satisfy > the condition. > Now if you could please check out this new problem i'm facing,related to > this.In my code,l4 is a list of lists, and these lists contain such pairs. > e.g. l4 = > [[[4,2],[4,7],[4,10],[4,12],[9,2],[9,7],[9,10],[9,12],[11,2],[11,10]],[[1,2],[3,5],[7,8]]] > which is a list of 2 lists (having 13 pairs) > Now when l4 has 50 pairs, and i run the code, python just hangs, and i'm > quite sure its because of this. Is there any way to rectify this??? > Yes: use standard debugging techniques.
You might try adding "print" statements to show you the value of various names as you run through the code: frequently this is good enough to explain what's going wrong (although you *do* need enough confidence to be able to predict what the values should be). If all else fails try the "stuffed bear" technique: sit an inanimate object in front of you and explain the code, and exactly why it can't possibly be going wrong. Amazingly often, halfway through your explanation you realise what your error is. regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Love me, love my blog http://holdenweb.blogspot.com Recent Ramblings http://del.icio.us/steve.holden -- http://mail.python.org/mailman/listinfo/python-list
