Le Lundi 12 Juin 2006 11:06, Girish Sahani a écrit : > Thanks!It worked....i wasted a lot of time trying to find a bug in my > code...what is wrong in iterating over a list and modifying it? > Doesnt python take the modified list every time the loop starts?
Python iterates over an iterator, that means calling it.next() method at each step. Is the iteration is consistent or not when you modify your iterable depends on the implementation of the iterator, but in general case it's a bad idea, and absolutely error prone. > Also in this case, i want to add a condition that if none of the pairs are > in pairList, element = []. How can i do that? element ? I guess it's already the case with lst = [ e for e in lst if e in pairs ] In [1]: lst = (1,2,3,4) In [2]: pairs=(5,) In [3]: lst=[e for e in lst if e in pairs] In [4]: lst Out[4]: [] -- _____________ Maric Michaud _____________ Aristote - www.aristote.info 3 place des tapis 69004 Lyon Tel: +33 426 880 097 -- http://mail.python.org/mailman/listinfo/python-list
