Lance Hoffmeyer <[EMAIL PROTECTED]> writes:
> So, I have using the following to grab numbers from MS Word. I
> discovered that that there is a "special" rule being used for
> rounding.
>
> If a ??.5 is even the number is to rounded down (20.5 = 20)
> if a ??.5 is odd the number is to rounded up (21.5 = 22)
This sounds specific enough that I'd want it in a separate function.
def specially_rounded_integer(num):
""" Round a number using our special rules """
rounded_num = num * phase_of_moon() # or whatever else you need to do
return rounded_num
> Brands = ["B1","B2"]
> A1 = []
> A1 = [ re.search(r"(?m)(?s)\r%s.*?SECOND.*?(?:(\d{1,3}\.\d)\s+){2}" % i,
> target_table).group(1) for i in Brands ]
> A1 = [int(float(str(x))+0.5) for x in A1 ]
> print A1
original_nums = however_you_get_them()
rounded_nums = [specially_rounded_integer(n) for n in original_nums]
If it's not quickly obvious on a single line, express it more
fully. Future readers, including yourself, will thank you.
--
\ "Nothing in life is so exhilarating as to be shot at without |
`\ result." -- Winston Churchill |
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Ben Finney
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