Lance Hoffmeyer wrote:
> So, I have using the following to grab numbers from MS Word. I discovered
> that that there is a "special"
> rule being used for rounding.
>
> If a ??.5 is even the number is to rounded down (20.5 = 20)
> if a ??.5 is odd the number is to rounded up (21.5 = 22)
>
> Brands = ["B1","B2"]
> A1 = []
> A1 = [ re.search(r"(?m)(?s)\r%s.*?SECOND.*?(?:(\d{1,3}\.\d)\s+){2}" % i,
> target_table).group(1) for i in Brands ]
> A1 = [int(float(str(x))+0.5) for x in A1 ]
> print A1
>
>
> Any solutions for this line with the above conditions?
Seems like a job for Decimal:
from decimal import Decimal
numbers = "20.50 21.5".split()
ZERO_PLACES = Decimal("1")
print [int(Decimal(num).quantize(ZERO_PLACES)) for num in numbers]
produces
[20, 22]
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