>From the Python 2.4 docs:
findall( pattern, string[, flags])
Return a list of all ***non-overlapping*** matches of pattern in
string....
By design, the regex functions return non-overlapping patterns.
Without doing some kind of looping, I think you are out of luck.
If you pattern is fixed, then a solution might be:
>>>string = 'abababababababab'
>>>pat = 'aba'
>>>[pat for s in re.compile('(?='+pat+')').findall(string)]
['aba', 'aba', 'aba', 'aba', 'aba', 'aba', 'aba']
If the pattern is not fixed (i.e. 'a.a') then this method can still get
a count of overlapping matches, but cannot get the individual match
strings themselves.
A simple loop should do in this case, though:
>>> for i in range(len(string)):
... r= re.match(pat,string[i:])
... if r: print r.group()
...
aba
aba
aba
aba
aba
aba
aba
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