Mirco Wahab wrote: > Py: > import re > tx = 'a1a2a3A4a35a6b7b8c9c' > rg = r'(\w)(?=(.\1))' > print re.findall(rg, tx)
The only problem seems to be (and I ran into this with my original example too) that what gets returned by this code isn't exactly what you are looking for, i.e. the numbers '1', '2', etc. You get a list of tuples, and the second item in this tuple contains the number, but also the following \w character. So there still seems to be some work that must be done when dealing with overlapping patterns/look-ahead/behind. Oh wait, a thought just hit me. Instead of doing it as you did: rg = r'(\w)(?=(.\1))' Could you do: rg = r'(\w)(?=(.)\1)' That would at least isolate the number, although you'd still have to get it out of the list/tuple. -- http://mail.python.org/mailman/listinfo/python-list
