Eric wrote: > I have a string... > > str = "tyrtrbd =ffgtyuf == =tyryr =u=p ttttff" > > I want to replace the characters after each '=', what I ended up doing is > somthing like this... > > buf = list(str) > newchr = '#' > > count = 0 > for i in range(len(buf)): > if buf[count] == '=': > buf[count + 1] = newchr > count = count + 1 > else: > count = count + 1 > > newstr = ''.join(buf) > > Is there a better, faster way of doing it? Using somthing like > str.index() dosn't work because... > > str = "hello world" > for i in str: > print str.index(i) > > 0 > 1 > 2 > 2 > 4 > 5 > 6 > 4 > 8 > 2 > 10 > > Every 'e' in "hello world" has the same index value. Am i missing somthing?
Split the string on '=', and join it back with '=#'. s='=#'.join(s.split('=')) -Larry Bates -- http://mail.python.org/mailman/listinfo/python-list