On 06/05/06, Eric <[EMAIL PROTECTED]> wrote: > I have a string... > > str = "tyrtrbd =ffgtyuf == =tyryr =u=p ttttff" > > I want to replace the characters after each '=', what I ended up doing is > somthing like this... > > buf = list(str) > newchr = '#' > > count = 0 > for i in range(len(buf)): > if buf[count] == '=': > buf[count + 1] = newchr > count = count + 1 > else: > count = count + 1 > > newstr = ''.join(buf) > > Is there a better, faster way of doing it? Using somthing like > str.index() dosn't work because... >
After you find an '=' you are updating the next chr in the list to '#' then testing the '#' to see if it is an '=' . This would be quicker as it bypasses testing your self-added '#' , and also removes a " count +1" #Untested buf = list(str) newchr = '#' count = 0 for i in range(len(buf)): if buf[count] == '=': count = count + 1 buf[count] = newchr count = count + 1 I might have done something like this (using s instead of str) #untested >>> buf = list(s) >>> newstr = '' >>> while buf: ... newstr += buf.pop(0) # get the first item in buf and append it to newstr ... if new[-1] == '=': ... newstr += '#' ... buf.pop(0) # discard the next item in buf HTH :) -- http://mail.python.org/mailman/listinfo/python-list
