Thomas Bartkus schrieb: > If I insert an __init__ method in my own class definition, it is incumbent > upon me to call the __init__ of any declared ancester to my new class object > because my __init__ will override that of any ancester I declare in the > header. If I fail to call the ancesters __init__, then it won't happen. > The ancester object won't be initialized. Yes.
> But > > If I *don't* insert my own __init__ in my new class, then any declared > ancester __init__ will automatically run because I haven't overridden the > ancesters __init__ method with my own. No. Only the __init__ of the leftmost ancestor is called. Of course if that uses the super(..)-method the other constructors get called. Diez -- http://mail.python.org/mailman/listinfo/python-list
