I V wrote:

> Note that print gets called after _each_ time that printBackward
> returns. So, as the different calls to printBackward return, they print
> whatever 'head' was set to in that invocation. Now, logically enough,
> the last call to printBackward is the first to return, so the last
> value of 'head' is printed first, and so in in the reverse order of the
> list.

Oh, that helps! Now I'm starting to understand when exactly it returns 
each time.
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