On 2006-02-28, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> Quoting Derek Basch <[EMAIL PROTECTED]>:
>
>> Given a value (x) that is within the range (1e-1, 1e7) how do I round
>> (x) up to the closest exact logarithmic decade? For instance:
>
> How about this:
>
> def roundup(x):
> if x < 1:
> return 1
> else:
> return '1' + ('0' * len(str(int(x))))
Interesting approach. You're converting to string at the same
time. I would guess the OP wanted a float.
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