Quoting Derek Basch <[EMAIL PROTECTED]>:

> Given a value (x) that is within the range (1e-1, 1e7) how do I round
> (x) up to the closest exact logarithmic decade? For instance:

How about this:

def roundup(x):
    if x < 1:
        return 1
    else:
        return '1' + ('0' * len(str(int(x))))

Jack Orenstein


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