As mentioned in the thread, it makes sense to build the desired output
you want from the tuple, rather than converting the tuple to a string
and then doing replace operations on the string.
If you do want to go the replace route, you don't need the power of
regex substitutions for what you are interested in. Just try the
replace method:
>>> foo = "('sometext1', 1421248118, 1, 'P ')"
>>> foo.replace("\'", "").replace("(", "").replace(")", "")
'sometext1, 1421248118, 1, P '
or, more elegantly:
>>> "".join([x for x in foo if x not in ['(',')','\''] ])
'sometext1, 1421248118, 1, P '
However, all of these replace-based solutions are bad because they will
not only replace the apostrophes and parentheses between the strings,
but also within them; what if "sometext1" is actually "John's Text?"
You are much better off building your desired output from the actual
tuple data yourself.
[EMAIL PROTECTED] wrote:
> hi
> i have some output that returns a lines of tuples eg
>
> ('sometext1', 1421248118, 1, 'P ')
> ('sometext2', 1421248338, 2, 'S ')
> and so on
> ....
>
> I tried this
> re.sub(r" '() ",'',str(output)) but it only get rid of the ' and not
> the braces. I need to write the output to a file such that
>
> sometext1, 1421248118, 1, P
> sometext2, 1421248338, 2, S
>
> I also tried escaping , re.sub(r" '\(\) ",'',str(output)) but also did
> not work
> How can i get rid of the braces before writing to file? thanks
>
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