[EMAIL PROTECTED] wrote: > I am a little annoyed at why such a simple program in Perl is causing > so much difficulty for python, i.e: > > $a += 200000 * 140000; > > print $a; > Yes, an annoying feature of the Python interpreter is that it doesn't always interpret Perl correctly.
You will find, though, that print 200000 * 140000 works quite well in both languages (with or without the trailing semi-colon). Variables in Python don't need a $ or @ to indicate whether they are scalar or structured - that depends on their value. So a = 0 a += 200000 * 140000 should also work quite well. Note the first assignment is needed because while there's no need to declare variables, you cannot assume a value until they have been assigned one (in Pythonic jargon "bound to a value"). What does "+=" mean in Perl, by the way? Does it just assume $a is zero if it isn't currently existent? happily-forgotten-perl-ly y'rs - steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC www.holdenweb.com PyCon TX 2006 www.python.org/pycon/ -- http://mail.python.org/mailman/listinfo/python-list
