> > > for i,v in enumerate(L):
> > > if v == X:
> > > L[i] = Y
> >
> > Here's an alternate solution using a replacement dictionary:
> >
> > M = {X:Y}
> > for i, v in enumerate(L):
> > L[i] = M.get(v, v)
[Fredrik Lundh]
> but that's 2-3 times slower than the OP's corrected code for his use
> case, so I'm not sure it qualifies as more "efficient"...
The alternate wasn't presented for efficiency. Its virtue is that with
no additional effort, it generalizes to substituting multiple
find/replace pairs in a single pass.
Raymond
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