I don't know of a way to directly access the internal structure of a long, but you can speed up your example.
First, is the order of the commands > i=i>>1 > lstBitsBitwiseAnd.append(i&0x01) what you intend? The first low order bit is discarded because you've done the shift first. And an extra 0 is appended. If you are trying to get the binary representation of a long, try i.__hex__(). This will create a string with the hex representation. Conversion from hex to binary is left as an exercise for the reader. :-) -- http://mail.python.org/mailman/listinfo/python-list
