Claudio Grondi wrote:
> The question is if Python allows somehow access to the bytes of the
> representation of a long integer or integer in computers memory?
Not sure what you mean by "Python", and "allows" here. I allow you :-)
To do so, write a C file that is a Python module, and accesses the
internal representation of the long. Works super-fast.
You can get somewhat faster in Python than your code if you avoid
producing new long objects all the time, and do the task in chunks of 30
bits.
Regards,
Martin
import time
repeats = [None]*100
start = time.clock()
for repeat in repeats:
i = 123456789**123
lstBitsBitwiseAnd = []
while i:
lstBitsBitwiseAnd.append(i&0x01)
i=i>>1
print time.clock()-start
start = time.clock()
for repeat in repeats:
i = 123456789**123
lstBitsBitwiseAnd = []
done = False
while i:
i1 = int(i & 0x3FFFFFFF)
i >>= 30
if i == 0: done = True
for k in xrange(30):
lstBitsBitwiseAnd.append(i1 & 1)
i1 >>= 1
if done and i1==0:
# if this is the top word, and no bits are left,
# we are done
break
print time.clock()-start
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