Antoon Pardon wrote: > Except when your default is a list > > class foo: > x = [] # default > > a = foo() > a.x += [3] > > b = foo() > b.x > > This results in [3]. So in this case using a class variable x to > provide a default empty list doesn't work out in combination > with augmented operators.
This has nothing to do with namespacing at all, it's the Python idiosyncracy about operations on mutable types. In this case, += mutates an object, while + returns a new one -- as by definition, for mutables. -- http://mail.python.org/mailman/listinfo/python-list
