Antoon Pardon <[EMAIL PROTECTED]> writes: ...
> Fine, we have the code: > > b.a += 2 > > We found the class variable, because there is no instance variable, > then why is the class variable not incremented by two now? Because it really is executed as: b.a = b.a + 2 1. get 't'b.a and store it in a temporary 't' (found the instance) 2. add 2 to 't' 3. store 't' in 'b.a' The last operation stores it into an instance variable. > > > Remember, Python is a dynamic language. > > So? Python being a dynamic language doesn't prevent the following to fail: > > >>> a=1 > >>> def f(): > ... a += 2 > ... > >>> f() > Traceback (most recent call last): > File "<stdin>", line 1, in ? > File "<stdin>", line 2, in f > UnboundLocalError: local variable 'a' referenced before assignment See the 'global' keyword. s. -- http://mail.python.org/mailman/listinfo/python-list
