Thank you for all the answers, some people have already answered for me about most details I don't agree :-)
Mike Meyer>Rexx has a global control that lets you set the number of digits to be considered significant in doing an FP equality test.< Mathematica too, I think. Tom Anderson>There are all sorts of solutions, coming at the problem from different angles, but the end of it is more or less here:< Interesting, but I think in Python the recursive solutions cannot be used, because they are too much fragile (they break with not much nested levels), an iterative solution (using a stack) can manage enough levels before finishing the memory ("not much" and "enough" are relative things, I know... but there is probably a difference of 10**4 times still). Note that statistically most real-life structures to flatten are probably quite flat (the most common are probably of depth 2), so probably the non recursive solution is the better again :-) Another problem with such solutions is that they don't allow to define what to iterate over and what to not consider a sequence. This is probably easy to define with an input parameter. (A compromise solution is probably enough, without a fully general solution for this problem). Another interesting possibility (suggested from Mathematica Flatten[] syntax) is to add another parameter to specify how much levels to flatten (all levels, only the first k levels, or all levels but the last n levels), but maybe this last parameter can be a bit less easy to remember, and Python functions are designed to be very easy to remember. Bye, bearophile -- http://mail.python.org/mailman/listinfo/python-list