Terry Reedy wrote:
> "Ron Adam" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
>
>>Actually I think I'm getting more confused. At some point the function
>>is wrapped. Is it when it's assigned, referenced, or called?
>
>
> When it is referenced via the class.
Ok, that's what I suspected. Thanks for clarifying this.
> If you lookup in class.__dict__, the function is still a function.
Now why did I not think of doing that? :-)
>>>>class C(object):
>
> ... def meth(self): pass
> ...
>
>>>>C.__dict__['meth']
>
> <function meth at 0x0090B018>
>
>>>>C.meth
>
> <unbound method C.meth>
>
>>>>C().meth
>
> <bound method C.meth of <__main__.C object at 0x008E4688>>
Ok, I got it now. Given class 'C' below, i.m(1) does....
>>> class C(object):
... def m(self, x):
... return repr(x)
...
>>> i = C()
>>> boundmeth = i.__getattribute__('m')
>>> boundmeth
<bound method C.m of <__main__.C object at 0x009D1C70>>
>>> boundmeth(1)
'1'
>>> import dis
>>> dis.dis(boundmeth)
3 0 LOAD_GLOBAL 0 (repr)
3 LOAD_FAST 1 (x)
6 CALL_FUNCTION 1
9 RETURN_VALUE
>>> dis.dis(C.m)
3 0 LOAD_GLOBAL 0 (repr)
3 LOAD_FAST 1 (x)
6 CALL_FUNCTION 1
9 RETURN_VALUE
>>> dis.dis(C.__dict__['m'])
3 0 LOAD_GLOBAL 0 (repr)
3 LOAD_FAST 1 (x)
6 CALL_FUNCTION 1
9 RETURN_VALUE
Hmm... that didn't tell me anything. (?)
>>> boundmeth
<bound method C.m of <__main__.C object at 0x009D1C70>>
>>> C.m
<unbound method C.m>
>>> C.__dict__['m']
<function m at 0x009D6930>
Time to start digging around in the source code I guess. ;-)
> I am not sure, without looking, how much of this is language definition and
> how much CPython implementation, but I think mostly the latter, as long as
> the inheritance tree lookup behavior is as specified.
>
> Terry J. Reedy
Yes, it hard to tell sometimes where CPython ends and Python begins.
Cheers,
Ron
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