I’m not understanding the task. The sample code given is converting the input
r’\x0a’ to a newline, it appears.
import re
def exam(z):
print(f"examine {type(z)} {z}")
for c in z:
print(f"{ord(c)} {c}")
s0 = r'\x0a'
def to1byte(matchobj):
return chr(int('0x' + matchobj.group(1), 16))
s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)
exam(s0)
exam(s1)
---
examine <class 'str'> \x0a
92 \
120 x
48 0
97 a
examine <class 'str'>
10
From: Python-list <python-list-bounces+gweatherby=uchc....@python.org> on
behalf of Jach Feng <jf...@ms4.hinet.net>
Date: Wednesday, December 7, 2022 at 9:27 PM
To: python-list@python.org <python-list@python.org>
Subject: Re: How to convert a raw string r'xdd' to 'xdd' more gracefully?
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Peter Otten 在 2022年12月8日 星期四清晨5:17:59 [UTC+8] 的信中寫道：
> On 07/12/2022 03:23, Jach Feng wrote:
> > s0 = r'\x0a'
> > At this moment it was done by
> >
> > def to1byte(matchobj):
> > ....return chr(int('0x' + matchobj.group(1), 16))
> > s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)
> >
> > But, is it that difficult on doing this simple thing?
> >>> import codecs
> >>> codecs.decode(r"\x68\x65\x6c\x6c\x6f\x0a", "unicode-escape")
> 'hello\n'
Thank you. What I really want to handle is to any r'\xdd'. The r'\x0a' is for
example. Sorry, didn't describe it clearly:-)
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