s0 = r'\x0a'
At this moment it was done by
def to1byte(matchobj):
....return chr(int('0x' + matchobj.group(1), 16))
s1 = re.sub(r'\\x([0-9a-fA-F]{2})', to1byte, s0)But, is it that difficult on doing this simple thing? --Jach -- https://mail.python.org/mailman/listinfo/python-list
