For completeness, from 3.5 onwards, you can also do the following:
[{'name': n, **d} for n, d in dod.items()]
On Tue, Mar 30, 2021 at 1:06 PM Chris Angelico <ros...@gmail.com> wrote:
> On Tue, Mar 30, 2021 at 11:01 PM Jon Ribbens via Python-list
> <python-list@python.org> wrote:
> >
> > On 2021-03-30, Chris Angelico <ros...@gmail.com> wrote:
> > > I dunno about "canonical", but here's how I'd do it:
> > >
> > > lod = [info | {"name": name} for name, info in dod.items()]
> > >
> > > You could use {"name":name}|info instead if you prefer to have the
> > > name show up first in the dictionary.
> >
> > It's probably worth noting this method requires Python 3.9.
>
> True, and if you need 3.8 support, then the dict constructor with one
> kwarg is the way to do it. But this way has the flexibility that you
> can choose which way to resolve conflicts (if there's a name inside
> the info dict, should it override the key, or not?).
>
> ChrisA
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