On Mon, Mar 22, 2021 at 9:11 PM Robert Latest via Python-list
<python-list@python.org> wrote:
>
> Hello,
>
> I'm trying to set up a server that receives data on a Unix domain socket using
> the code below.
>
> import os from socketserver import UnixStreamServer, StreamRequestHandler
>
> SOCKET = '/tmp/test.socket'
>
> class Handler(StreamRequestHandler):
>
> def handle(self): data = selr.rfile.read() print(data)
>
> if os.path.exists(SOCKET): os.unlink(SOCKET) with UnixStreamServer(SOCKET,
> Handler) as server: server.serve_forever()
Hmm, your formatting's messed up, but the code looks fine to me. (Be
aware that you seem to have a "selr" where it should be "self".)
> However, when I try to send somthing to that socket, I get this error message:
>
> $ echo "Hello" | socat - UNIX-SENDTO:/tmp/test.socket 2021/03/22 11:03:22
> socat[2188] E sendto(5, 0x55a22f414990, 6, 0, AF=1 "/tmp/test.socket", 18):
> Protocol wrong type for socket
>
Not familiar with socat, but here's some simple Python code to trigger
your server:
>>> import socket
>>> sock = socket.socket(socket.AF_UNIX)
>>> sock.connect("/tmp/test.socket")
>>> sock.send(b"Hello, world")
12
>>> sock.close()
>>>
Once you close the socket, the request handler should respond.
ChrisA
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