Hello,
I'm trying to set up a server that receives data on a Unix domain socket using
the code below.
import os from socketserver import UnixStreamServer, StreamRequestHandler
SOCKET = '/tmp/test.socket'
class Handler(StreamRequestHandler):
def handle(self): data = selr.rfile.read() print(data)
if os.path.exists(SOCKET): os.unlink(SOCKET) with UnixStreamServer(SOCKET,
Handler) as server: server.serve_forever()
However, when I try to send somthing to that socket, I get this error message:
$ echo "Hello" | socat - UNIX-SENDTO:/tmp/test.socket 2021/03/22 11:03:22
socat[2188] E sendto(5, 0x55a22f414990, 6, 0, AF=1 "/tmp/test.socket", 18):
Protocol wrong type for socket
I don't understand that error. Here's /tmp/test.socket:
$ stat /tmp/test.socket
File: ‘/tmp/test.socket’
Size: 0 Blocks: 0 IO Block: 4096 socket
Device: fd00h/64768d Inode: 201443577 Links: 1
Access: (0775/srwxrwxr-x) Uid: ( 1001/ dh) Gid: ( 1001/ dh)
Context: unconfined_u:object_r:user_tmp_t:s0
Access: 2021-03-22 09:47:49.516298102 +0100
Modify: 2021-03-22 09:47:49.516298102 +0100
Change: 2021-03-22 09:47:49.516298102 +0100
Birth: -
Sadly all examples I can find on the web are for TCP sockets, not Unix domain.
Any tips?
robert
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