> On Oct 28, 2020, at 5:49 AM, ktkelly_1 <kjk...@gmail.com> wrote:
>
> Currently have a code that takes in a .txt file and submits commands to the
> serial. Then it reads the reply from the serial port and writes it to a
> hardcoded .txt file. The problem is it doesn't save it live and so if I need
> to stop the code for any reason, I can't gather current data and the text
> file is blank. I'm not as familiar with buffering and things like that and
> tried "outputFile = open("./outputFile.txt", "a", 0)" but that gave me the
> error "can't have an unbuffered text I/O” in python 3?" so I'm not sure what
> to do. Here is the general layout if you would like to mess around with it:
from os import fsync
> with open(test_file) as file_test:
> Lines = file_test.readlines()
> for line in Lines:
> #send_str is the command to send to the serial port
> send_str = line
> file_result.write(line + "\n") #<--- if I were to cancel out after
> this it wouldn't be saved(*)
file_result.flush()
os.fsync()
>
> ser.write(send_str.encode('utf-8'))
> time.sleep(send_pause)
> reply_str = ser.readline().decode('utf-8').strip()
> file_result.write("reply:" + reply_str + "\n") #<---(*)
> file_result.write('\n') #<---(*)
file_result.flush()
os.fsync()
Karen
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