Currently have a code that takes in a .txt file and submits commands to the serial. Then it reads the reply from the serial port and writes it to a hardcoded .txt file. The problem is it doesn't save it live and so if I need to stop the code for any reason, I can't gather current data and the text file is blank. I'm not as familiar with buffering and things like that and tried "outputFile = open("./outputFile.txt", "a", 0)" but that gave me the error "can't have an unbuffered text I/O” in python 3?" so I'm not sure what to do. Here is the general layout if you would like to mess around with it:
with open(test_file) as file_test: Lines = file_test.readlines() for line in Lines: #send_str is the command to send to the serial port send_str = line file_result.write(line + "\n") #<--- if I were to cancel out after this it wouldn't be saved(*) ser.write(send_str.encode('utf-8')) time.sleep(send_pause) reply_str = ser.readline().decode('utf-8').strip() file_result.write("reply:" + reply_str + "\n") #<---(*) file_result.write('\n') #<---(*) anything helps thank you in advanced -- https://mail.python.org/mailman/listinfo/python-list