Thanks guys for the help on this. As it turns out I have learned new commands as a result of the question: all() and any() will work perfectly! The other solutions, as always, are enlightening. And, no, Chris, this is not homework :)
On Tue, Jan 8, 2019 at 9:31 AM Neil Cerutti <ne...@norwich.edu> wrote: > On 2019-01-08, MRAB <pyt...@mrabarnett.plus.com> wrote: > > On 2019-01-08 00:47, i...@koeln.ccc.de wrote: > >> You might do something like > >> > >> if len(a) == 0 or all(i == a[0] for i in a[1:]): > >> > > You don't need to check the length of the list because if the list is > > empty, 'all' will return True anyway. > > Neat! I expected that a[0] would be executed in that case, > but it is not. > > -- > Neil Cerutti > -- > https://mail.python.org/mailman/listinfo/python-list > -- **** Listen to my FREE CD at http://www.mellowood.ca/music/cedars **** Bob van der Poel ** Wynndel, British Columbia, CANADA ** EMAIL: b...@mellowood.ca WWW: http://www.mellowood.ca -- https://mail.python.org/mailman/listinfo/python-list
