You might do something like
if len(a) == 0 or all(i == a[0] for i in a[1:]):
This should be linear complexity and short circuiting and in general it
doesn't get much better than this. Though I wouldn't bet there isn't a
better (faster/clearer/more readable) solution.
On Mon, Jan 07, 2019 at 05:14:14PM -0700, Bob van der Poel wrote:
> I need to see if all the items in my list are the same. I was using set()
> for this, but that doesn't work if items are themselves lists. So, assuming
> that a is a list of some things, the best I've been able to come up with it:
>
> if a.count( targ ) == len(a):
>
> I'm somewhat afraid that this won't scale all that well. Am I missing
> something?
--
https://mail.python.org/mailman/listinfo/python-list
