On 2018-11-21 19:18, Python wrote:
$ python3
Python 3.5.2 (default, Nov 23 2017, 16:37:01)
[GCC 5.4.0 20160609] on linux
Type "help", "copyright", "credits" or "license" for more information.
1 in [1,2,3] == True
False
1 in ([1,2,3] == True)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: argument of type 'bool' is not iterable
(1 in [1,2,3]) == True
True
How is the first not equivalent to either one of the second or third?
My expectation is it should produce the same result as the second. It
*seems* like Python is ignoring the '1 in' part and just giving the
result for '[1,2,3] == True'... Is this just a bug?
It's a chained comparison. It applies to '<', '<=', '>', '>=', '==' and
'!=', but also to 'in', although I've never seen a chained comparison
using 'in' in practice.
You can write:
1 <= x <= 10
which is equivalent to:
1 <= x and x <= 10
except that the 'x' part is evaluated only once (this matters if you
have, say, a function call there).
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