On Wed, Nov 21, 2018 at 01:18:22PM -0600, Python wrote: > $ python3 > Python 3.5.2 (default, Nov 23 2017, 16:37:01) > [GCC 5.4.0 20160609] on linux > Type "help", "copyright", "credits" or "license" for more information. > >>> 1 in [1,2,3] == True > False > >>> 1 in ([1,2,3] == True) > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > TypeError: argument of type 'bool' is not iterable > >>> (1 in [1,2,3]) == True > True > > How is the first not equivalent to either one of the second or third? > My expectation is it should produce the same result as the second. It > *seems* like Python is ignoring the '1 in' part and just giving the > result for '[1,2,3] == True'... Is this just a bug?
FWIW I meant my expectation is it should be the same as #3 (I confused the 2nd item with the second subsequent thing that it did not match) since "in" and "==" have the same precedence, and should be evaluated in order left to right. IOW, it should evaluate to True. -- https://mail.python.org/mailman/listinfo/python-list
