Sayth Renshaw wrote:
>
>> myjson = ...
>> path = "['foo']['bar'][42]"
>> print(eval("myjson" + path))
>>
>> ?
>>
>> Wouldn't it be better to keep 'data' as is and use a helper function like
>>
>> def get_value(myjson, path):
>> for key_or_index in path:
>> myjson = myjson[key_or_index]
>> return myjson
>>
>> path = ['foo', 'bar', 42]
>> print(get_value(myjson, path))
>>
>> ?
>
> Currently I do leave the data I extract the keys out as a full path.
>
> If I use pprint as suggested I get close.
>
> ['glossary'],
> ['glossary', 'title'],
> ['glossary', 'GlossDiv'],
> ['glossary', 'GlossDiv', 'title'],
> ['glossary', 'GlossDiv', 'GlossList'],
> ['glossary', 'GlossDiv', 'GlossList', 'GlossEntry'],
> ['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'ID'],
> ['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'SortAs'],
> ['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'GlossTerm'],
> ['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'Acronym'],
> ...]
>
> But to select elements from the json I need the format
> json['elem1']['elem2] .
>
> I want to be able to get any json in future and parse it into my function
> and return a list of all json key elements.
>
> Then using this cool answer on SO
> https://stackoverflow.com/a/14692747/461887
>
> from functools import reduce # forward compatibility for Python 3
> import operator
>
> def getFromDict(dataDict, mapList):
> return reduce(operator.getitem, mapList, dataDict)
Note that my -- not so cool ;) -- function
>> def get_value(myjson, path):
does the same in a way that I expected to be easier to understand than the
functional idiom.
> def setInDict(dataDict, mapList, value):
> getFromDict(dataDict, mapList[:-1])[mapList[-1]] = value
>
> Then get the values from the keys
>>>> getFromDict(dataDict, ["a", "r"])
> 1
>
>
> That would mean I could using my function if I get it write be able to
> feed it any json, get all the full paths nicely printed and then feed it
> back to the SO formula and get the values.
OK, if this is really just about printing
>>> path = ["foo", "bar", 42]
>>> print("".join("[{!r}]".format(key) for key in path))
['foo']['bar'][42]
>
> It would essentially self process itself and let me get a summary of all
> keys and their data.
>
> Thanks
>
> Sayth
--
https://mail.python.org/mailman/listinfo/python-list
