On 24/07/18 08:25, Mark Lawrence wrote:
> On 24/07/18 06:41, Sayth Renshaw wrote:
>> On Tuesday, 24 July 2018 14:25:48 UTC+10, Rick Johnson wrote:
>>> Sayth Renshaw wrote:
>>>
>>>> elements = [['[{0}]'.format(element) for element in elements]for
>>>> elements in data]
>>>
>>> I would suggest you avoid list comprehensions until you master
>>> long-form loops.
>>
>> I actually have the answer except for a glitch where on list element
>> is an int.
>>
>> My code
>>
>> for item in data:
>> out = '[{0}]'.format("][".join(item))
>> print(out)
>>
>> which prints out
>>
>> [glossary]
>> [glossary][title]
>> [glossary][GlossDiv]
>> [glossary][GlossDiv][title]
>> [glossary][GlossDiv][GlossList]
>> ....
>>
>> However, in my source I have two lines like this
>>
>> ['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'GlossDef',
>> 'GlossSeeAlso', 0],
>> ['glossary', 'GlossDiv', 'GlossList', 'GlossEntry', 'GlossDef',
>> 'GlossSeeAlso', 1],
>>
>> when it hits these lines I get
>>
>> TypeError: sequence item 6: expected str instance, int found
>>
>> Do I need to do an explicit check for these 2 cases or is there a
>> simpler way?
>>
>> Cheers
>>
>> Sayth
>>
>
> out = '[{0}]'.format("][".join(str(item)))
No.
>>> item = ['a', 'b', 1]
>>> '[{0}]'.format("][".join(item))
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: sequence item 2: expected str instance, int found
>>> '[{0}]'.format("][".join(str(item)))
"[[]['][a]['][,][ ]['][b]['][,][ ][1][]]"
>>>
You'll want to use map(), a generator comprehension, or a different
approach.
>
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