On 6/18/2018 8:38 PM, sa...@caprilion.com.tw wrote:
Grant Edwards at 2018/6/18 PM 10:36 wrote:
On 2018-06-17, Jach Fong <jf...@ms4.hinet.net> wrote:
C:\Python34\Doc>py
Python 3.4.4 (v3.4.4:737efcadf5a6, Dec 20 2015, 19:28:18) [MSC v.1600 32
bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
import tkinter as tk
root = tk.Tk()
tk.Label(root, text='label one', font='TkDefaultFont').pack()
from tkinter import font
font.nametofont('TkDefaultFont')
<tkinter.font.Font object at 0x021E9490>
font.nametofont('TkDefaultFont')
<tkinter.font.Font object at 0x021E9390>
The "address" of the Font object 'TkDefaultFont' changes, why?
What makes you think it's the same object the second time and not a
new object?
Simply from what the method's name "name-to-font" implied. The font is
already there, so naturally it should be the same one:-)
'nametofont' is a trivial function returning 'Font(name=name,
exists=True)'. As explained before, the address is the address of the
Python Font interface object, not the tk font structure. tk has a
mapping of font names to font structures. tkinter does not keep a dict
mapping names or font structures to Font instances, so each call to Font
returns a new Font instance.
--
Terry Jan Reedy
--
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