Jim Lee at 2018/6/17 PM 04:10 wrote:
On 06/17/2018 12:08 AM, Jach Fong wrote:
C:\Python34\Doc>py
Python 3.4.4 (v3.4.4:737efcadf5a6, Dec 20 2015, 19:28:18) [MSC v.1600
32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import tkinter as tk
>>> root = tk.Tk()
>>> tk.Label(root, text='label one', font='TkDefaultFont').pack()
>>> from tkinter import font
>>> font.nametofont('TkDefaultFont')
<tkinter.font.Font object at 0x021E9490>
>>> font.nametofont('TkDefaultFont')
<tkinter.font.Font object at 0x021E9390>
>>>
The "address" of the Font object 'TkDefaultFont' changes, why?
Best Regards,
Jach Fong
def nametofont(name):
"""Given the name of a tk named font, returns a Font representation.
"""
return Font(name=name, exists=True)
Every time you call nametofont(), you're creating a new instance of the
Font class.
hmm... It means every time I set a widget's font to
"TkDefaultFont", a new object was created. Why python do things this
way? Can't it use
this same object again and again?
--Jach
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